2.
[tex] \frac{2}{x + 2} - \frac{1}{2y + 2} = 3 \\ 2.\frac{1}{x + 2} - \frac{1}{2(y + 1)} = 3 \\ 2. \frac{1}{x + 2} - \frac{1}{2} . \frac{1}{y + 1} = 3[/tex]
Misal : 1/ x+2 = a
1/ y+1 = b
2a + ½b = 3.....(1) | ×2 | 4a + b = 6
a + b = 4.......(2) | ×1 | a + b = 4
---------------------------------------------------------- -
3a = 2
a = ⅔
Mencari b
a + b = 4
⅔ + b = 4
b = 4 - ⅔
b = 10/3 = 3⅓
[tex] \frac{1}{x + 2} = \frac{2}{3} \\ 2(x + 2) = 3 \\ 2x + 4= 3 \\ 2x = 3 - 4 \\ 2x = - 1 \\ x = - \frac{1}{2} [/tex]
[tex] \frac{1}{y + 1} = \frac{10}{3} \\ 10(y + 1) = 3 \\ 10y + 10 = 3 \\ 2y = 3 - 10 \\ 10y = - 7 \\ y = - \frac{7}{10} [/tex]
HP = ( x, y ) = ( -½, -7/10 )
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